However, it has some irrational properties. According to WolframAlpha, lim. The function f is probably injective for some values of a.
Math Equations
Sunday, June 22, 2014
A rational sinusoidal function
It is easy to get confused by the irrational nature of the sin function. One might think that you need irrational numbers to create a sinusoidal graph, but that's false. Consider za=(a+i)2/(a2+1)(a∈Rat). It lies on the unit circle in the complex plane and its coordinates are rational. Here is a rational sinusoidal function: f(x)=Im(zxa)(x∈Int). This is what it may look like:
Monday, June 16, 2014
Ugliest sequence ever
Let a_0 = 0, a_2 = 1 and a_n = a_{\left\lfloor{n/2}\right\rfloor} + a_{\left\lfloor{n/2}\right\rfloor+1}.
Wednesday, June 4, 2014
Basic interpolation
Say we've got n points through which we need to fit a polynomial. We'll solve the problem iteratively. First we'll find a polynomial that passes through one point, then we'll add a term to that polynomial to make it pass through another point, and then a third point will come into play -- etc.
Let the given points be \begin{array}{c}n\\(x_i, y_i)\\i=1\end{array} and let p_k denote the kth polynomial that we find. p_n is our final answer. p_k = \begin{cases}y_1 & \text{ if } k = 1\\ p_{k-1} + (y_k - p_{k-1}\bigg|_{x=x_k}) \prod_{i=1}^{k-1} \frac{x - x_i}{x_k - x_i} & \text{ if } 1 < k \leq n\end{cases}.
Let the given points be \begin{array}{c}n\\(x_i, y_i)\\i=1\end{array} and let p_k denote the kth polynomial that we find. p_n is our final answer. p_k = \begin{cases}y_1 & \text{ if } k = 1\\ p_{k-1} + (y_k - p_{k-1}\bigg|_{x=x_k}) \prod_{i=1}^{k-1} \frac{x - x_i}{x_k - x_i} & \text{ if } 1 < k \leq n\end{cases}.
Subscribe to:
Posts (Atom)